The correct order for acid strength of compou | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Acidic strength is directly proportional to the stability of the conjugate base.Stability of the conjugate base depends on the electronegativity o

Vedclass · Accepted Answer

$CH \equiv CH > CH_3 - C \equiv CH > CH_2 = CH_2$

Vedclass · Answer

(D) Acidic strength is directly proportional to the stability of the conjugate base.Stability of the conjugate base depends on the electronegativity of the carbon atom bearing the negative charge.The electronegativity order is $sp$ carbon ($50\% \ s$-character) > $sp^2$ carbon ($33.3\% \ s$-character) > $sp^3$ carbon ($25\% \ s$-character).$1$. $CH \equiv CH$ (ethyne) has $sp$ hybridized carbons.$2$. $CH_3 - C \equiv CH$ (propyne) has one $sp$ hybridized carbon,but the methyl group $(CH_3)$ is electron-donating ($+I$ effect),which destabilizes the conjugate base compared to ethyne.$3$. $CH_2 = CH_2$ (ethene) has $sp^2$ hybridized carbons,which are less electronegative than $sp$ carbons.Therefore,the correct order of acidic strength is $CH \equiv CH > CH_3 - C \equiv CH > CH_2 = CH_2$.

The correct order for acid strength of compounds $CH \equiv CH$,$CH_3 - C \equiv CH$,and $CH_2 = CH_2$ is as follows:

Similar Questions

Maximum bond energy of $C-H$ bonds is found in the compound:

The correct order of acidic nature of the following alkynes is:
$I$. $HC \equiv CH$
$II$. $CH_3-C \equiv C-CH_3$
$III$. $CH_3-C \equiv CH$

The simplest alkyne is represented by

In its reaction with silver nitrate,acetylene shows:

Which reagent can be used to distinguish between $1$-butyne and $2$-butyne?

Vedclass Test Series

Exam Paper Generator

Online Exam Module